Math, asked by jan13, 1 year ago

If 3x-8y=5 and xy=-2 find the value of 9x^2+64y^2

Answers

Answered by wwwkashyapreeta
0

Answer:

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Answered by draswin0655
5

Answer:

Step-by-step explanation:

Given:

3x-8y=5

xy=-2

To find:

9x^2+64y^2

Solution:

3x-8y=5

squaring on both sides

(3x-8y)^2=5^2

9x^2+64y^2-48xy=25

9x^2+64y^2-48(-2)=25 [since xy=-2]

9x^2+64y^2+96=25

9x^2+64y^2=25-96

9x^2+64y^2=-71

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