if 3x =cosec 7 and 3/x =cot find the vale of 3(x²-1/x²)
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3x = cosec 7
x = cosec 7 / 3
x2 = cosec2 7 / 9...... (i)
3/x = cot 7
1/x = cot 7 / 3
1/x2 = cot2 7 / 9...........(ii)
3(x2 - 1/x2) = 3(cosec2 7 /9 - cot2 7 /9)
3(cosec2× 7 - cot2 A / 9 )
3( 1 / 9)
3 X 1 / 9 = 1 / 3
so answer is 3(x2 - 1/x2) = 1 / 3 .
hope it helps u.....
x = cosec 7 / 3
x2 = cosec2 7 / 9...... (i)
3/x = cot 7
1/x = cot 7 / 3
1/x2 = cot2 7 / 9...........(ii)
3(x2 - 1/x2) = 3(cosec2 7 /9 - cot2 7 /9)
3(cosec2× 7 - cot2 A / 9 )
3( 1 / 9)
3 X 1 / 9 = 1 / 3
so answer is 3(x2 - 1/x2) = 1 / 3 .
hope it helps u.....
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