Question

if 3x=cosec theeta and 3/x=cot theeta fine the value of 3(x^3-1/x^2 please give me correct answer . ​

Answer 1

since it is given that 3x=cosec theta and 3/x=cot theta

so,x=cosec theta/3 & 1/x=cot theta/3

so,3(cosec theta^2/9 - cot^2/9)

3[1/9(cosec theta^2 - cot theta^2). -(1)

as we know that 1 + cot theta^2=cosec theta^2

1=cosec theta^2 - cot theta ^2. -(2)

putting value of (2) in (1)

1/3(1)

1/3

answer as soon as possible