If 3x=cosec theta and 3/x=cot theta, find the value of 3(x^2-1/x^2)
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3x=cscθ and x3=cotθ
⇒x=3cscθ and x1=3cotθ
3(x2+x21)=3⎝⎜⎜⎜⎜⎛(3cscθ)2+(3cotθ)21⎠⎟⎟⎟⎟⎞
=3(9csc2θ+cot2θ9)
=3(91+cot2θ+cot2θ9)
=3(9cot2θcot4θ+cot2θ+81)
=(3cot2θcot4θ+cot2θ+81)
=3cot2θcot2θ(cot2θ+1)+81
=3cot2θcot2θcsc2θ+81
=3cot2θcot2θcsc2θ+81
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