Question

if-3x is a root of equation kx^2+2x-3 then value of k is​

Answer 1

Answer:

k = 6 if ur question is a bit modified

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$k {x}^{2} + 2x - 3$

$x = - 3$

$k {( - 3)}^{2} + 2( - 3) - 3 = 0$

$9 {k}^{2} - 6 - 3 = 0$

$9 {k}^{2} - 9 = 0$

$9( {k}^{2} - 1) = 0$

${k}^{2} - 1 = 0$

${k}^{2} = 1$

$k = 1$