If 3x+k,2x+9 and x+3 are three consecutive terms of an AP find k
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anwinkp007:
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If these are in AP then the common difference would be same
So,
(2x+9)-(3x+k)=(x+3)-(2x+9)
2x+9-3x-k=x+3-2x-9
9-x-k= -x-6
9+6=k
15=k
So,
(2x+9)-(3x+k)=(x+3)-(2x+9)
2x+9-3x-k=x+3-2x-9
9-x-k= -x-6
9+6=k
15=k
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