Question

If 3x-k y-2=0, 2x+y+2= 0 are perpendicular, then the value of k is

Answer 1

Answer:

Step-by-step explanation:

In general, system of equations a1x+b1y+c1=0 & a2x+b2y+c2=0 will have no solution only if both the straight lines become parallel to each other & mathematical condition is

a1b1=a2b2

Setting the corresponding values from given system of equations: kx+2y=5 and 3x+y=1 in above condition, we get

k2=31

k=6

Now, k=6, there is no point of intersection which satisfy both the given linear equations in two variables x & y

But for any other value k≠6 there is a unique solution or infinite solutions