If 3x=sec theta,3÷x tan theta ,then ( x×x_1÷x×x)is equal to
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3x = sec∅ => x = secx/3
3/x = tan∅ => 1/x = tanx/3
then, (x² - 1)/x = x²/x - 1/x
= x - 1/x = (secx/3 - tanx/3)
= (secx - tanx)/3
hence, (x² - 1)/x = (sec - tanx)/3
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