Math, asked by studious40, 10 months ago

If 3x-y=12, find the value of 8^x/2^y.​

Answers

Answered by Niveditha647
2

Answer:

3x-y=12

8^x/2^y = 2^(3x) / 2^y

            = 2 ^ (3x - y )

            = 2 ^ 12

            = 4096 (answer )

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Answered by V07926LOVYANSH
0

Answer:

Step-by-step explanation:

ts simple,

8 =2^3 .

So 2^3x/2^y.

Using law of indices , 2^3x-y.

3x-y=12 from the given equation.

So 2^12.

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