Question

if 3x-y =12 what is the value of 8^x/2^y , who can answer it

Answer 1

hope this helps you......

Answer 2

Answer: The value cannot be determined from the given information

Step-by-step explanation:

You should start by trying to solve for a variable by getting one variable on the other side, then isolating. We'll start by isolating x, then substituting the answer into the equation to get y.

If you isolate and solve for x:

Start: 3x-y=12

Step 1: Add y to both sides

3x=y+12

Step 2: Divide both sides by 3 to isolate x completely

x=y/3+4

Step 3: We now know what x equals, so we can plug it back into the original equation

3(y/3+4)-y=12

Step 4: Distribute the 3 into (y/3+4)

y+12-y=12

Step 5: Combine like terms (positive and negative y cancel out)

12=12

We cancelled out y and are left with 12=12 so we need to try the exact same process, but instead isolate y and substitute it into the equation to get x.

Now let's try to isolate and solve for y:

Start: 3x-y=12

Step 1: Subtract 3x from both sides

-y=-3x+12

Step 2: Divide both sides by -1 to remove the negative and isolate y completely (basically flipping all the signs on both sides)

y=3x-12

Step 3: We now know what y equals, so we can plug it back into the original equation

3x-(3x-12)=12

Step 4: Distribute the negative (-1) into (3x-12)

3x-3x+12=12

Step 5: Combine like terms (positive and negative x cancel out)

12=12

We cancelled out x and are left with 12=12 once again. We cannot solve for either one of the variables and because of this there isn't enough information to evaluate 8^x/2^y.