Question

if 3x+y=5 and 6x+ay=7are intersecting lines then a

Answer 1

let 3x+y =5 ...............i
6x + ay = 7 ...............ii
now multiplying i by 2 v gt equation i =
6x +2 y = 10 .........iii
now add ii n iii equation
6x +ay = 7
+6x +2y = 10
v get y (a- 2) = -3
y = -3/(a-2) ...............iv
put in i v gt
3x -3/ (a-2) = 5
x = [5+3/(a-2)]/3(a-2)
x = [ 5(a-2)+ 3(a-2)]/3(a-2)²
x = 8(a-2)/3(a-2)²
x = 8/3(a-2) ............v
put iv n v in ii
6*8/3(a-2) -3a /(a-2) = 7
1/(a-2) [48/3 -3a ] = 7
1/(a-2) [48-9a/3] =7
48 -9a = 7*3*(a-2)
48 -9a = 21(a-2)
48 -9a =21a - 42
-9a - 21a = -42 -48
-30a = -90
a = 3 this is ur required answer
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