Math, asked by alvinmosesm, 1 year ago

If 3x+y+z=0, show that 27xcube +ycube + zcube

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Answered by Anonymous

4

3x+y+z=o

(3x) ^3+(y) ^3+(z) ^3=0. (taking cube in both sides)

27x^3+y^3+z^3=0

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