If 3x+y+z=0, show that 27xcube +ycube + zcube
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3x+y+z=o
(3x) ^3+(y) ^3+(z) ^3=0. (taking cube in both sides)
27x^3+y^3+z^3=0
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(3x) ^3+(y) ^3+(z) ^3=0. (taking cube in both sides)
27x^3+y^3+z^3=0
hope it hlps u
follow me
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