Question

If 3x10-3 J of work is done in moving a particle carrying a charge of 15x10-6 C from infinity to a point P, what will be the potential at the point P?

Answer 1

Answer:

Using the formula V(potential)=W(work done)/Q(charge), we get :

potential difference=200v

ans.

Answer 2

Answer:

• Potential difference is 200

Explanation:

Note -

For finding the value of volt the formula is used

$\huge\boxed{\red{V = \frac{W}{q} }}$

Where, V is Volt

W is total work done

q is total charge

Given :

W = 3 × 10-³ J

q = 15 × 10^-16 C

To Find :

The potential difference at the point P

Solution :

V = W \ q

V = 3×10-³/ 15×10^-16

V = 3×10-³×10^6/ 15

V = 1×10^-3+6/ 5

= 10³/ 5 = 1000/5

$\boxed{\pink{200}}$