Question

If 3x2+8ax+3 is a perfect square,then find the value of a

Answer 1

Step-by-step explanation:

$3 {x}^{2} + 8ax + 3 = > 3( {x}^{2} + \frac{8}{3}ax + 1)$

${x}^{2} + \frac{8}{3}ax + 1 \: should \: be \: equal \: to \:$

${x}^{2} + 2x + 1$

So that it is a perfect square hence

$\frac{8}{3}a = 2 = > a = \frac{6}{8} = \frac{3}{4}$

Hope it helps you.