Question

If 3x2 - ax + 6 = ax2 + 2x + 2 has only one (repeated) solution, then the positive integral solution of a is:

Answer 1

this is the appropriate answer for your question

Answer 2

Answer: 2

Step-by-step explanation:

3(x^2)-ax+6 = a(x^2)+2x+2

=> (x^2)(3-a)-x(a+2)+4=0

If a quadratic equation(ax^2+bx+c=0) has equal roots, then discriminant should be zero i.e. b^2-4ac=0

Here a=3-1 ; b=-(a+2) ; c=4

(-(a+2))^2 - 4(3-a)*4 = 0

a^2 + 4 + 4a - 16(3-a)=0

a^2 + 4 + 4a - 48 + 16a = 0

a^2 + 20a - 44 = 0

(a+22)(a-2)=0

a=2

When a=2, equation becomes (x^2)(3-2)-x(2+2)+4=0

x^2-4x+4 =0

x=2