If 3xy4 is divisible by 9 where x, and y are two digits, then
(a) x + y = 2
(b) x + y = 11
(c) Either x + y = 2 or x + y = 11
d) Neither x + y = 2 nor x + y = 11
Answers
Either x + y = 2 or x + y = 11 is 3xy4 is divisible by 9
Given : 3xy4 is divisible by 9 where x, and y are two digits,
To Find : Choose correct option
(a) x + y = 2
(b) x + y = 11
(c) Either x + y = 2 or x + y = 11
d) Neither x + y = 2 nor x + y = 11
Solution:
3xy4 is divisible by 9
"A number is divisible by 9 if some of digits is divisible by 9"
Sum of Digits of 3xy4
= 3 + x + y + 4
= 7 + (x + y)
x + y can be from 0 to 18
Hence
7 + (x + y) can be between 7 and 25
numbers between 7 and 5 divisible by 9 are
9 , 18
7 + (x + y) = 9 => x + y = 2
7 + (x + y) = 18 => x + y = 11
Hence correct option is c) Either x + y = 2 or x + y = 11
Either x + y = 2 or x + y = 11 is 3xy4 is divisible by 9
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