If (3y-1),(3y+5)and (5y+1)are three consecutive number of A P then find the value of y .
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The value of the is 5
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Answer:
The answer is y=6
Step-by-step explanation:
3y-1,3y+1,5y-1
Here,
a=3y-1,
an=5y-1,
n=3 and
d=3y+5-3y+1=6
an=a+(n-1)a
5y-1=3y-1+(3-1)6
5y-1-3y+1=2x6
2y=12
y=12/2
therefore,y=6
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