Math, asked by kdsingh2514, 2 months ago

If

3y -1, 3y+5 and 5y+1
are three
Consecutive terms
an AP then
value of y?

Answers

Answered by srinivasnatte2789

1

Answer:

3y-1,3y+5,5y+1

3y-3y

0

5-5y=y

-1+1=0

then y=0

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