If 3y - 1, 3y + 5 and 5y + 1 are three consecutive terms of an A.P., then find the value of y.
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Answered by
12
Answer:
The first 3 terms of A.P. are (3y−1),(3y+5),(5y+1).
Therefore,
2(3y+5)=3y−1+5y+1
6y+10=8y
2y=10
y=5
Answered by
10
Answer:
Value of y is 5.
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