Question

if 3y-1/3y=7 find 9y squre+1/9y square
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Answer 1

Answer:

$\frac{3y - 1}{3y} = 7$

$3y - 1 = 21y$

$18y = - 1$

$y = \frac{ - 1}{18}$

$9y {}^{2} + \frac{1}{9y {}^{2} }$

$9( \frac{ - 1}{18} ) {}^{2} + \frac{1}{9( \frac{ - 1}{18} ) {}^{2} }$

Answer 2

Answer:

answer

Step-by-step explanation:

9(-1/18)^2+1/9(-1/18)^2