Question

if (3y-2)+i(7+2x)=0 then x =
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Answer 1

Answer:

(3y-2) + i (7-2x) =0

For a complex number to be 0, both real and imaginary part must be zero.

So, 3y-2=0 and 7–2x=0

<=> 3y=2 and 2x=7

<=> y=2/3 and x=7/2.

For complex x and y

(3y-2) + i (7-2x) =0

<=> 3y-2+7i-2xi=0

<=>3y=2xi-7i+2

<=>y=(2xi-7i+2)/3

Step-by-step explanation:

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