if 3y+5 =20then find 3y+5+20+1
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Answered by
1
Given --3y + 5 = 20 ..........(i)
3y + 5 + 20 + 1
= (3y + 5) + 20 + 1
= 20 + 20 + 1 .....from (i)
= 41
3y + 5 + 20 + 1
= (3y + 5) + 20 + 1
= 20 + 20 + 1 .....from (i)
= 41
Answered by
1
answer is 41 . 3y+5=20 . so y=5. substitute the value of y as 5 in the equation 3(5)+5+20+1. to get the answer as 41
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