If 3y + x > 2 and x + 2y ≤ 3, What can be said about the value of y?
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Answer:y€[-3+x/2,-2+x/3)U(2-x/3,3-x/2]
Step-by-step explanation: We have,
3y+x>2 & x+2y<=3,
so, from 3y+x>2we have, y>2-x/3 so taking this as equestion no. 1,
and from x+ 2y<=3 we have, y<=3-x/2 again taking this as equestion no. 2,
so assuming a= 2-x/3 & b= 3-x/2
then, we get, a<y<=b
now,
on putting the value of a & b in a<y<=b we get,
2-x/3<y<=3-x/2
therefore y € [-3+x/2,-2+x/3)U(2-x/3,3-x/2]
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