Question

If 3y²=18y then roots of quadratic equation is​

Answer 1

Answer:

3y²-18y=0

3y(y-6)=0

hope this helps you

please mark me as the brainliest

Step-by-step explanation:

Answer 2

Answer:

3y²=18y

3y²-18y=0

3y(y-6)=0

3y=0,. y-6=0

y=0. y=6

Step-by-step explanation:

hope it helps ☺️......