Question

If 4.00 moles of N2 and 3.00 moles of H2 are allowed to react according to the reaction N2(g) + 3H2(g) --> 2NH3(g). The number of molecules of the gas left unreacted will be :
A)1.86 x 10^23
B)6.02 x 10^23
C)18.1 x 10^23
D)1.20 x 10^23

Answer 1

Answer:

Explanation:

moles n2 unreacted = 3

molecules un reacted = 18.069*10^23