Question

if (-4,-1),(-2,1)and(k,3) are collinear then find K value?​

Answer 1

Answer:

Given that,

A(-4,-1), B(-2,1) and C(k,3)

if the points are collinear then area of the triangle is equal to zero.

Area of ∆ABC=1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|

0=1/2|-4(1-3)-2(3+1)+k(-1-1)|

0×2=|-4(-2)-2(4)+k(-2)|

0=|12-8-2k|

0=4-2k

2k=4

k=4/2

k=2

therefore, the required value of k=2

Hope it works..................................™✌️✌️