If (4,1) be an end of a diameter of the circle x2 + y2 – 2x + 6y - 15 = 0 then the other
end of the diameter is
(a)
(4,0) (b)
(-2,4) (c)
(7,4)
(d)
(-2,-7)
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I don't know if you have seen this before and you know that
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