If 4 (10/x)^2- 6 (10/x)^2+ 3(10/x)^2 = 1, then find the value of ‘x’.
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(2^3x-1 +10)÷7=6
(2^3x-1 +10)/7=6
(2^3x-1 +10)=42
2^3x-1=42–10=32
(2)^3x-1=(2)^5
3x-1=5
3x=6
x=6/3
x=2 , Answer
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