Math, asked by paechuarsenal6362, 1 month ago

If 4 (10/x)^2- 6 (10/x)^2+ 3(10/x)^2 = 1, then find the value of ‘x’.

Answers

Answered by swapnabindutata
0

Answer:

(2^3x-1 +10)÷7=6

(2^3x-1 +10)/7=6

(2^3x-1 +10)=42

2^3x-1=42–10=32

(2)^3x-1=(2)^5

3x-1=5

3x=6

x=6/3

x=2 , Answer

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