Question

if 4*10²⁰ eV is required to move a charge if 0.25 colomb between two points the potential difference between these two points is​

Answer 1

Answer:

$4$ × $10^{20} eV = 4$ × $10^{20}$ × 1.6 × $10^{-19}$ = 64J

So E = 64 = V × Q = 0.25V

V = 256V