Question

if 4.2 mole of oxygen is required in formation of potassium chlorate when react with KCL. calculate the mass of KCL and KCLO3 also calculate volume of kcl​

Answer 1

Answer:

Decomposition of KClO

3

takes place as:

2KClO

3

(s)→2KCl(s)+3O

2

(g)

2 mole of KClO

3

=3 mole of O

2

∵ 3 mole O

2

formed by 2 mole KClO

3

∴2.4 mole of O

2

will be formed by:

(

3

2

×2.4) mol KClO

3

= 1.6 mole of KClO

3

.

Mass of KClO

3

= Number of moles × Molar mass

=1.6×122.5=196g