if 4(2^x-1)+9(3^y-1)=17 and 3(2^x)-2(3^y)=6 then x+y =
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4(2^x-1)+9(3^y-1)=2(2^x)+3(3^y)=17
3(2^x)-2(3^y)=6
Let 2^x=p and 3^y=q
Then two equations become
2p+3q=17 and 3p-2q=6
Now multiply 1st equation by 3 and 2nd equation by 2 then subtract 2nd equation from 1st, you will get 13q=39
q = 39/13= 3
By putting this value of q in any of the above equations you will get p=4
q=3^y=3=3^1
y=1
p=2^x=4=2^2
x=2
x+y=2+1=3 Ans
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