if (4+2i) (1+2i)=A +iB then
1)A=0 2)B=0 3)A=10 4)B=0
Answers
Answered by
0
Answer:
the answer is a=0
and b=10i
Answered by
2
Answer:
option A
Step-by-step explanation:
Given that:-
(4+2i)(1+2i)=A+iB
=>(4×1)+(2i×1)+(4×2i)+(2i×2i)=A+iB
=>4+2i+8i+4i²=A+iB
=>4+10i+4i²=A+iB
=>4+10i+4(-1)=A+iB
=>4+10i-4=A+iB
=>0+10i=A+iB
On comparing both sides then
A=0 and B=10
A=0
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