Math, asked by chhemasri143, 4 months ago

if (4+2i) (1+2i)=A +iB then
1)A=0 2)B=0 3)A=10 4)B=0​

Answers

Answered by deveshchoudhary15
0

Answer:

the answer is a=0

and b=10i

Answered by tennetiraj86
2

Answer:

option A

Step-by-step explanation:

Given that:-

(4+2i)(1+2i)=A+iB

=>(4×1)+(2i×1)+(4×2i)+(2i×2i)=A+iB

=>4+2i+8i+4i²=A+iB

=>4+10i+4i²=A+iB

=>4+10i+4(-1)=A+iB

=>4+10i-4=A+iB

=>0+10i=A+iB

On comparing both sides then

A=0 and B=10

A=0

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