if 4^2x+1=8^x+3then X
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x = 7
Step-by-step explanation:
Given :
4^{2x + 1} = 8^{x + 3}
To find :
The value of x.
Solution :
4^{2x + 1} = 8^{x + 3}
{2^{2} )}^{2x + 1} = {({2}^{3}) }^{x + 3}
⟹ 2^(4x + 2) = 2^(3x + 9)
⟹ 4x + 2 = 3x + 9
⟹ 4x − 3x = 9 −2
⟹ x = 7
Hence, x = 7.
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