If 4+3√3/√(4+2√3)=C+D√3 then find C-D
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Length of three of its sides are given AB = 6 cm, BC = 8 cm, CD = 4 cm, AD = ? ... (a) b (c) 2b a c (b) b √ac (d) b=a-c 199 In ΔABC, b = 2, c = √3 & A = 30° then in-radius
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