If (4)^3 * (6)^4 * (10)^5 = 2^x *3^y * 5^z, then the value of x+y+z is
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0
Answer:
Given,
2
x
×3
y
×5
z
=2160,
2160=2×2×2×2×3×3×3×5
2160=2
4
×3
3
×5
1
by comparision, we get,
x=4,y=3,z=1
3
x
×2
−y
×5
−z
=3
4
×2
−3
×5
−1
=
2
3
×5
3
4
=
40
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