Math, asked by mayankandharsh1236, 10 months ago

If (4, 3) and (-12, -1) are end points of a
diameter of a circle, then the equation of the
circle is-​

Answers

Answered by Meenamahajan37
0

Answer:

this can't be possible as diameter can't be in negative nom

Answered by SushmitaAhluwalia
3

The equation of the circle with ends of diameter (4, 3) and (-12, -1) is x^{2}+y^{2}+8x-2y-51=0

  • The equation of circle with ends of the diameter as (x_{1},y_{1}) and (x_{2},y_{2}) is given by

                (x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0-----(1)

  • Given, ends of the diameter are

                (x_{1},y_{1})=(4,3)

                 (x_{2},y_{2})=(-12,-1)

  • Substituting above values in (1), we get

                (x-4)(x+12)+(y-3)(y+1)=0

                 x^{2}+12x-4x-48+y^{2}+y-3y-3=0

                 x^{2}+y^{2}+8x-2y-51=0

  • Therefore, the equation of required circle is x^{2}+y^{2}+8x-2y-51=0
Similar questions