Question

If -4, -3 are zeroes of x2+ax+b then value of a2-4b is.

Answer 1

Answer:

we know...we can write an quadratic expression. in the form

x²-(sum of roots)x+ ( product of roots)

x²-(-4-3)x +(-4•-3)

x²-(-7)x +(12)

x²+7x+12 ----------(1)

x²+ax+b -----------(2)

comparing expression 2 with one 1

we get the value of a=7 and value of b=12

a²-4b = (7)²-4•12

=49-48

=1