if 4√3 is a root of a quadratic equation, then find the equation.
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Answer:
x²-8x+19=0
Explanation:
Given 4-i√3,is a root of equation
⇒4-i√3,4+i√3 are two roots
L+B=4+i√3+4-i√3
=8
L+B=(4+i√3)(4-i√3)
=19
Equation⇒x²-(l+b) x+l b=0
⇒x²-8x+19=0
Quadratric equation is=
x²-8x+19=0
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