Question

if 4/3 (sec^2 59°- cot^2 31°) - 2/3 sin 90° + 3 tan^2 56° tan^2 34°=x/3

Answer 1

Answer:

4( sec^2 59 - cot^2 (90-59)/3) -2/3 (1) +3 tan^2 56* tan^2 (90-56)

4(sec^2 59- tan^2 59/3) -2/3 +3 tan^2 56* cot^2 56

4(1/3)-2/3+3(1)

4/3-2/3+3/1

4-2+9/3

= 11/3

Answer 2

HOPE IT HELPS YOU..

@RUKSHI