Question

If (4,-3x/5) is the mid point of the line segment joining the points Q (2,-5) and R (-2,-4) then the value of x is
a) -8
b) 16
C) 15/2 D) 8

Answer 1

Answer:

C) 15/2

Step-by-step explanation:

Here is your solution!!

Answer 2

The value of x is $\frac{15}{2}$

Step-by-step explanation:

Given that $(4,-\frac{3x}{5})$ is the mid point of the line segment joining the points Q (2,-5) and R (-2,-4)

To find the value of x in the mid point :

• Let $(x_1,y_1)$ and  $(x_2,y_2)$ be the given points Q (2,-5) and R (-2,-4) respectively
• Let M(x,y) be the mid point $(4,-\frac{3x}{5})$

The formula for midpoint is $M(x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

• Now substitute the points in formula we get

• $(4,-\frac{3x}{5})=(\frac{2-2}{2},\frac{-5-4}{2})$
• $(4,-\frac{3x}{5})=(\frac{0}{2},\frac{-9}{2})$

Now equating $-\frac{3x}{5}=\frac{-9}{2}$

• $-3x\times 2=-9\times 5$
• $6x=45$
• $x=\frac{45}{6}$
• $x=\frac{15}{2}$

Therefore the value of x is $\frac{15}{2}$

Therefore the option c) $\frac{15}{2}$ is correct