Math, asked by piyushkumar959898, 5 hours ago

If 4* - 4*-1 = 24 find the value of x

Answers

Answered by Anonymous
12

Correct question:

If \sf 4^{x}-4^{x-1} = 24, find the value of x.

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Solution:

  • \sf 4^{x} can be written as \sf 2^{2x}
  • \sf 4^{x-1} can be written as \sf 2^{2x-2}

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\sf 2^{2x} - 2^{2x-2} = 24

\sf 2^{2x} - 2^{2x} \times 2^{-2}= 24

Take \sf 2^{2x} as common:

\sf 2^{2x} (1-2^{-2} )= 24

\sf 2^{2x} (1- \dfrac {1}{4})= 24

\sf 2^{2x} (\dfrac {4-1}{4})= 24

\sf 2^{2x} (\dfrac {3}{4})= 24

\sf 2^{2x} = 24 \div \dfrac {3}{4}

\sf 2^{2x} = 24 \times \dfrac {4}{3}

\sf 2^{2x} = 8 \times 4

\sf 2^{2x} = 2^{3} \times 2^{2}

\sf 2^{2x} = 2^{3+2}

\sf 2^{2x} = 2^{5}

On equating powers of 2:

2x = 5

\boxed {\bf {\red {x = \dfrac {5}{2}}}}

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Value of x:

Value of x is \underline {\sf {\purple {\dfrac {5}{2}}}}

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