Question

If 4/5,a, 2 are three consecutive terms of an A.P., then find the value of a​

Answer 1

Answer:

a = 7/5

Step-by-step explanation:

4/5 , a, 2 are in AP

a1 = 4/5 a2 = a a3 = 2

then the common difference d is equal

a2 - a1 = a3 - a2

$a - \frac{4}{5} = 2 - a \\ \frac{5a - 4}{5} = 2 - a \\ 5a - 4 = 5(2 - a) \\ 5a - 4 = 10 - 5a \\ 5a + 5a = 10 + 4 \\ 10a = 14 \\ a = \frac{14}{10} \\ a = \frac{7}{5}$

verification

$\frac{7}{5} - \frac{4}{5} = 2 - \frac{7}{5} \\ \frac{7 - 4}{5} = \frac{10 -7 }{5} \\ \frac{3}{5} = \frac{3}{5} \\ common \: diference \: = \frac{3}{5}$

Hope you get your answer