Question

if 4/5,a,2 are three consecutive terms of an A.P.,then find its common differences

Answer 1

here is the answer.....

hope this would help you....

all the best for your board exams......

Answer 2

Answer:

$Common\: difference (d)=\frac{3}{5}$

Step-by-step explanation:

$Given,\: \frac{4}{5},a,2\: \\are \: three \: consecutive\: terms\\ \: in \: A.P$

$Let \: a_{1}=\frac{4}{5},\:a_{2}=a,\: a_{3}=2$

\*We know that ,

Difference of any two consecutive terms are equal in A.P*/

$a_{2}-a_{1}=a_{3}-a_{2}$

$\implies a-\frac{4}{5}=2-a$

$\implies 2a= 2+\frac{4}{5}$

$\implies 2a= \frac{10+4}{5}$

$\implies a = \frac{14}{10}$

$\implies a = \frac{7}{5}$

$Now, \\ Common\: difference (d)= a_{2}-a_{1}\\=a-\frac{4}{5}\\=\frac{7}{5}-\frac{4}{5}\\=\frac{7-4}{5}\\=\frac{3}{5}$

Therefore,

$Common\: difference (d)=\frac{3}{5}$

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