if 4/5,a,2 are three consecutive terms of an AP than find a
Answers
Answered by
7
4/5 , a , 2 are in A.P
so
a-4/5=2-a
5a-4 / 5 = 2-a
5a - 4 = 10 - 5a
5a + 5a = 10+ 4
10a = 14
a = 14/10
a = 7/5
so
a-4/5=2-a
5a-4 / 5 = 2-a
5a - 4 = 10 - 5a
5a + 5a = 10+ 4
10a = 14
a = 14/10
a = 7/5
Answered by
13
Answer : 7/5
Step-by-step explanation :
If x, y, z are the consecutive terms of an A. P then 2y = x + z.
Given, 4/5, a, 2 are the consecutive terms of an Arithmetic progression,
As said above,
2 ( a) = 4/5 + 2
2a = 4/5 + 10/5
2a = 14/5
a = 14/10
a = 7/5
Therefore a = 7/5
Step-by-step explanation :
If x, y, z are the consecutive terms of an A. P then 2y = x + z.
Given, 4/5, a, 2 are the consecutive terms of an Arithmetic progression,
As said above,
2 ( a) = 4/5 + 2
2a = 4/5 + 10/5
2a = 14/5
a = 14/10
a = 7/5
Therefore a = 7/5
Hakar:
awesome
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