if 4/5 ,a ,2 are three consecutive terms of an AP then find the value of 5 of a
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We know that the difference of the first and second term and the third term are equal
So, now the the second term is half the sum of the first and the third term :=
4/5+2 = 2a
4+10/2=2a in LHS the 4+10 is
whole upon 10
14=4a
a=14/4
a=7/2
Therefore we can conclude that the second term is 7/2
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