If 4/5 , a , 2 are three consecutive terms of an AP then find a.
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Three consecutive terms are :-
(a-d), a, (a+d)
Here
a-d = 4/5. -------1equation
a =a
a+d = 2 ----------2equation
Add both equations,
a-d = 4/5
a+d =2
2a = 4/5 +2
2a = (4+10)/5
a = 14/10
a = 7/5 or 1.4
I hope this will help you
-by ABHAY
(a-d), a, (a+d)
Here
a-d = 4/5. -------1equation
a =a
a+d = 2 ----------2equation
Add both equations,
a-d = 4/5
a+d =2
2a = 4/5 +2
2a = (4+10)/5
a = 14/10
a = 7/5 or 1.4
I hope this will help you
-by ABHAY
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