If 4/5,a,2 three consecutive term of an appointment then find a
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if 4/5 ,a,2 are consecutive , then
a-4/5= 2-a
5a-4/5=2-a
5a-4=10-5a
10a=14
a=14/10
a=7/5
a-4/5= 2-a
5a-4/5=2-a
5a-4=10-5a
10a=14
a=14/10
a=7/5
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