Question

If 4

5

, a and 2 are the three consecutive terms of an A.P., then find the value of a.​

Answer 1

Term of a.p. = 4/5 , a , 2

d = a2 - a1

d = a - 4/5 = 2 - a

   = 5a-4/5  = 2 - a

   = 5a - 4 = 5(2 - a)

   = 5a - 4 = 10 - 5a

   = 10a = 14

   = a = 14/10

   = a = 7/5

hence 3 term will be 4/5 , 7/5 , 2

   = d = 7/5 - 4/5

so difference = 3/5 (Answer).