if 4/5 of a water tank is filled in 1 hour how much time will be required to fill the rest of it. .(without taking x) .i will tell him brainiest ......tell with explanation
Answers
Step-by-step explanation:
Hi there!
Here's the answer:
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
Let full part of tank = x
(4/5)th of water tank fills in 1 Hour i.e., 60 minutes
=> (4/5)×x ------ 60 minutes.
=> 4x = 300 minutes
=> x = 75 minutes
•°• Total part of tank gets filled in75 minutes.
Remaining part of tank to be filled
= x - (4x/5) = x/5
This part will be get filled in (75 - 60) minutes = 15 minutes.
•°• Time required to fill rest of tank = 15 minutes.
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
MARK AS BRAINLIEST....
Answer:
Step-by-step explanation:
Let full part of tank = x
(4/5) th of water tank fills in 1 Hour i.e., 60 minutes
=> (4/5)×x ------ 60 minutes.
=> 4x = 300 minutes
=> x = 75 minutes
•°• Total part of tank gets filled in 75 minutes.
Remaining part of tank to be filled
= x - (4x/5) = x/5
This part will be get filled in (75 - 60) minutes = 15 minutes.
•°• Time required to fill rest of tank = 15 minutes.