If 4 /5 of a water tank is filled in 1 hour, how much time will be required to fill the rest of it?
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Answered by
33
Hi there!
Here's the answer:
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
Let full part of tank = x
(4/5)th of water tank fills in 1 Hour i.e., 60 minutes
=> (4/5)×x ------ 60 minutes.
=> 4x = 300 minutes
=> x = 75 minutes
•°• Total part of tank gets filled in75 minutes.
Remaining part of tank to be filled
= x - (4x/5) = x/5
This part will be get filled in (75 - 60) minutes = 15 minutes.
•°• Time required to fill rest of tank = 15 minutes.
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
©#£€®$
:)
Hope it helps
Here's the answer:
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
Let full part of tank = x
(4/5)th of water tank fills in 1 Hour i.e., 60 minutes
=> (4/5)×x ------ 60 minutes.
=> 4x = 300 minutes
=> x = 75 minutes
•°• Total part of tank gets filled in75 minutes.
Remaining part of tank to be filled
= x - (4x/5) = x/5
This part will be get filled in (75 - 60) minutes = 15 minutes.
•°• Time required to fill rest of tank = 15 minutes.
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
©#£€®$
:)
Hope it helps
Answered by
2
Answer:
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Step-by-step explanation:
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